1. divide 6 and 6, both sides will not equal 0 ]. z/ x# [1 l; C" ~2. take any side of the 6, divide then 3 and 3, again both sides will not equal9 Z; m8 j& K" h7 m. I
3. take any 2 and weigh them 6 g( \) W; |9 r4 C) x$ C; A' S' h- }if they equal, the one left is the ball.