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回復 #1 MagicAndy 的帖子

i wan to know
thx.~
thank you for sharing
look at it
i noe de ans cauz 1 do b4 already ^^0 y% \0 m7 n: \* ^3 e3 H, j4 }
1st u divide the ball into two group (i group 6 ball)
/ d" n  t+ w/ N. V+ ^) a& Z, pthen 称 them c which side is the heavy
; |: M2 R3 W5 Y7 X% y, L6 [tvb now,tvbnow,bttvbthen use the heavy side divide into 3 group 1group contain 2 ball 称 the 1st n 2nd group if its balance use the 3th group
5 u- D1 ^! V$ @' S5 J9 J; Z% NTVBNOW 含有熱門話題,最新最快電視,軟體,遊戲,電影,動漫及日常生活及興趣交流等資訊。if not balance take the heavy and then
: E) p- f. \. r4 \1 jtvb now,tvbnow,bttvbtake the heavy group divided into 2 group i group contain 1 ball than 称 it tvb now,tvbnow,bttvb; P  d6 @9 a8 {" H  l+ Y
than the heavy ball is the ball u wan

回復 #1 MagicAndy 的帖子

how??????????
Oh..i did the same way as the first answer~am i wrong??Let me check~:onion18:
分三次算的话,每次分四粒来算,意思说当有一边较重时,只需要随意将其中六粒拿出来就知道那一粒是异常的了:onion14: tvb now,tvbnow,bttvb0 X$ A+ \; \- M: e
(不知各位知不知道小弟说的解答,因为小弟不擅长解说)
thx 4 sharing
顶......

回復 #1 MagicAndy 的帖子

顶.......
简单到。。分3份。。每份4个。。第一次称。。必然知道3份中哪份包括异常的。。第二次..把包括的那份2:2的称。。又知道异常的一边
4 e" u, N8 Y$ p, s9 D0 J6 k/ M5 Htvb now,tvbnow,bttvb然后。。1:1。。就知道了··
看解答!!!!!!!!!!!!!!
cccccc
idk..show me
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