1 1 1, because any number can have factor of 1. also, only 1 can be true if any random number multiple plus has to be divided by the remaining digit. So, 1 1 1 is my answer.
They would be 111 or 123" v: C( D' B1 G
For 111 would be 1x1+1=2 that is 2 times of 3rd 1& _2 u* }5 n$ D- J
For 123 * h: C- H; ?$ Q! E& G1x2+1=3 that is 1 time of 3os.tvboxnow.com/ i4 n* D3 B- Q/ N7 V0 Y. {2 q
1x3+1=4 that is 2 times of 2 3 M6 h9 [7 M( W5 q" P9 y' r$ h2x3+1=7 thta is 7 times of 1