put six on each side first0 ?- s% i2 L. T% V
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from the heavier six, split it to three on each side
+ l2 y; G) q% i5 `6 d+ m2 \& Ktvb now,tvbnow,bttvb
0 e- L( ~" { v# F+ e$ Q4 Ios.tvboxnow.comthen there is three left, put one on each side, if one is heavier then that is it, if they are balanced then last one is heavy one |