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答案!!!!!!!!!答案!!!!!!!!!!!答案!!!!!!!!!!!!!1
^:)^ >:D<
thx
let cc
not possible
不知道要怎麼做阿??
hao

the model answer is stupid

there got more simple way to do it, just read my way, the one i answered before
the
see 了
第一次,一边5个称,若质量没有异常就只称剩下的2个就知道异常的那个了;若有异常就把异常的那5个用一边2个称第二次,若没有异常就是剩下的那个异常了,若有异常就把异常的那2个再2一边1个称第三次就知道了
how?
先分3个一堆
$ o/ a6 B9 x& |- K: @! vos.tvboxnow.com共四堆
' m+ |$ D( r! j公仔箱論壇称两次得出异常的在那一堆,其轻重
  J& I7 D0 ^6 ?% n# v公仔箱論壇在异常的那一堆中在称一次
1 D" k$ r3 H. H. [- g& K公仔箱論壇就可以找到了
divde the 12 balls into 3 sets of 4.
% R& `. s4 B0 r3 Q* W公仔箱論壇weight any 2 sets./ w% L) m5 p  A6 \2 m$ y  X6 Q# s
if the 2 sets are equal, then you know the heavy one is in the third
. u+ ~+ D& U; m$ S% z9 e& L, e3 K) V* ttvb now,tvbnow,bttvbif one of the 2 is heavier, then the heavy one is in that setos.tvboxnow.com4 e1 ]+ W2 x. R3 p- }- F" X/ f
then divide the 4 balls into 2.公仔箱論壇- W8 R5 Q# i; t
weigh themos.tvboxnow.com' R' t/ }% J/ n% p5 x# ]
and divide the heavier into 1os.tvboxnow.com! \  S7 y1 a9 c: I
and weight them.* ~- g. u" R1 t7 H0 @, h! [% [( u% W# o
3 x weighing and get the ans.  
5 U# [: F! Y- @7 F, O4 Y4 a公仔箱論壇in less than 15 secs.
1. 6 aside and weight.
8 g" S& q" v$ ^5 D1 _9 uos.tvboxnow.com2. heavier side from (1), 3 aside weight again.
' Y8 q3 L# s5 z1 s3 m$ t- T3. heavier side from (2), take 2 out of 3 to weight. If equal weight the one not on the scale is the heavier one. else the heavier one on the scale is the odd one. os.tvboxnow.com8 E* H6 w) u$ g' e9 T/ E7 A+ A

9 W) Q5 |' ?. t+ o# }* i0 kbut i have a question. 重量異常 can be heavier or lighter.... so......
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