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see xia da an
want to know
我来看看
check ans..
6 and 6 then 3 and 3 then 1 and 1
5識答?
thank you
将12个乒乓球分成平均两份,称一次
) N2 E% |, |* A! _将比较重的那份再平均分成两份成一次! z! h3 o, R/ V7 V* A- u
剩下3个随意拿两个来称,如果天平平衡就是第三个,如果不平衡就是重的那个
thank
Thanks!
第一次系一边四个,一边四个秤既
1 - compare 4 with 4' ~2 Y! F5 {3 b1 F3 o+ b# {
if  (4v4)= same that means the rest of 4 is got more weight1 i/ B$ C7 T% E5 ^3 O: Q5 W" q0 b
    then goto 2 - compare rest of(4)  - 2 with 2
$ C. t2 O! E& Z3 NTVBNOW 含有熱門話題,最新最快電視,軟體,遊戲,電影,動漫及日常生活及興趣交流等資訊。           if (left side is more weight)公仔箱論壇4 v, @, A8 I4 @2 z, d% a
              then goto 3 - compare last (left side of ( 2) - 1 with 1 => get answer
/ J3 C0 ]  {( o: _& m5 Bos.tvboxnow.com          else ( right side is more weight)
: ]9 {9 o. q* Y, Fos.tvboxnow.com              then goto 3 - compare last (right side of (2) - 1 with 1 => get answer
/ ^1 P4 T5 S! J, Otvb now,tvbnow,bttvbelse ( the left 4) then compare with above  , or right 4 also can compare above method...
想了好久都不行
我的做法与4楼的做法一致,这样应该可以排除出来。但这个题目有个漏洞,只说重量异常,没说是重了,还是轻了。
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