返回列表 回復 發帖

回復 #1 MagicAndy 的帖子

i wan to know
thx.~
thank you for sharing
look at it
i noe de ans cauz 1 do b4 already ^^
0 \. K  E) k/ W3 Y, E8 o5 Q公仔箱論壇1st u divide the ball into two group (i group 6 ball)
' x/ A1 @, O  ?2 z8 Btvb now,tvbnow,bttvbthen 称 them c which side is the heavy os.tvboxnow.com- Q- o6 p9 w$ _5 [. i
then use the heavy side divide into 3 group 1group contain 2 ball 称 the 1st n 2nd group if its balance use the 3th group os.tvboxnow.com% w' B; y* H4 H
if not balance take the heavy and then 4 b& ?% c2 q& k! `" L4 ]/ X: R! V
take the heavy group divided into 2 group i group contain 1 ball than 称 it
( K: ^- F9 g' v5 Q" g3 ?# G公仔箱論壇than the heavy ball is the ball u wan

回復 #1 MagicAndy 的帖子

how??????????
Oh..i did the same way as the first answer~am i wrong??Let me check~:onion18:
分三次算的话,每次分四粒来算,意思说当有一边较重时,只需要随意将其中六粒拿出来就知道那一粒是异常的了:onion14: os.tvboxnow.com2 f- {) d/ ^1 t5 z7 V2 h2 o
(不知各位知不知道小弟说的解答,因为小弟不擅长解说)
thx 4 sharing
顶......

回復 #1 MagicAndy 的帖子

顶.......
简单到。。分3份。。每份4个。。第一次称。。必然知道3份中哪份包括异常的。。第二次..把包括的那份2:2的称。。又知道异常的一边公仔箱論壇. x2 `8 R: l6 ~7 Z$ ]" |# ]
然后。。1:1。。就知道了··
看解答!!!!!!!!!!!!!!
cccccc
idk..show me
返回列表