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答案!!!!!!!!!答案!!!!!!!!!!!答案!!!!!!!!!!!!!1
^:)^ >:D<
thx
let cc
not possible
不知道要怎麼做阿??
hao

the model answer is stupid

there got more simple way to do it, just read my way, the one i answered before
the
see 了
第一次,一边5个称,若质量没有异常就只称剩下的2个就知道异常的那个了;若有异常就把异常的那5个用一边2个称第二次,若没有异常就是剩下的那个异常了,若有异常就把异常的那2个再2一边1个称第三次就知道了
how?
先分3个一堆os.tvboxnow.com+ ~, A4 u& J9 p! i+ y- B
共四堆; x, H+ `- r" f# B/ h- ^* \1 j5 }
称两次得出异常的在那一堆,其轻重公仔箱論壇8 \; c4 X' O  Q6 v) Y7 \0 w
在异常的那一堆中在称一次os.tvboxnow.com3 T+ v, A. ?2 {$ i* |
就可以找到了
divde the 12 balls into 3 sets of 4. 4 y8 D& s  t! n* @" ^
weight any 2 sets.tvb now,tvbnow,bttvb: D2 ?) `% p; y; t! ?' d. x
if the 2 sets are equal, then you know the heavy one is in the thirdtvb now,tvbnow,bttvb4 O4 W* u" K% S
if one of the 2 is heavier, then the heavy one is in that set
5 y! n- z% a3 j" f" H( V公仔箱論壇then divide the 4 balls into 2.2 R/ S1 X* s* @: Y
weigh themos.tvboxnow.com, [# k0 V% n- b+ a3 U! h( t7 K
and divide the heavier into 1tvb now,tvbnow,bttvb8 @7 a/ b2 _, d& M
and weight them.
+ I) A+ n- q/ g6 Pos.tvboxnow.com3 x weighing and get the ans.  
4 _- y5 E" M/ D" X, S9 \8 |- `os.tvboxnow.comin less than 15 secs.
1. 6 aside and weight.4 o, t0 L$ P- T' A8 n/ v& t
2. heavier side from (1), 3 aside weight again.公仔箱論壇( S& h' s6 _* @0 A) U- J) P
3. heavier side from (2), take 2 out of 3 to weight. If equal weight the one not on the scale is the heavier one. else the heavier one on the scale is the odd one.
: q8 a: a# ^# O. k) x' j' @: [8 ^公仔箱論壇公仔箱論壇$ h- Q! A. ?* S9 Y
but i have a question. 重量異常 can be heavier or lighter.... so......
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