zzzhao

see xia da an

yaukinman

want to know

zb7803

我来看看

lkhlewis

青蓮居士

check ans..

mkl2345

6 and 6 then 3 and 3 then 1 and 1

gg2968

5識答？

pyhzf

thank you

XYZCrux

将12个乒乓球分成平均两份，称一次公仔箱論壇6 ^1 i, }1 k4 b8 n
将比较重的那份再平均分成两份成一次
- \+ }8 E1 E' Y4 `/ c剩下3个随意拿两个来称，如果天平平衡就是第三个，如果不平衡就是重的那个

wtfka

thank

agnesium

Thanks!

ban0212

第一次系一边四个，一边四个秤既

westgun

1 - compare 4 with 4TVBNOW 含有熱門話題，最新最快電視，軟體，遊戲，電影，動漫及日常生活及興趣交流等資訊。- `% E: C+ m7 @1 L/ m2 m/ B
if  (4v4)= same that means the rest of 4 is got more weightos.tvboxnow.com! i# h3 l9 u# {0 A1 O+ N5 o
    then goto 2 - compare rest of(4)  - 2 with 2 tvb now,tvbnow,bttvb" u% S% F% O3 d8 p! D
           if (left side is more weight)tvb now,tvbnow,bttvb6 u5 B. f  e. B, ^, j4 D) n- w. f! l$ A
              then goto 3 - compare last (left side of ( 2) - 1 with 1 => get answertvb now,tvbnow,bttvb3 V' t8 M9 F5 H% e( ]
          else ( right side is more weight)
% a! C4 y" Y" ~5 qos.tvboxnow.com              then goto 3 - compare last (right side of (2) - 1 with 1 => get answer
! c& N- ~6 u6 U2 L/ E# nos.tvboxnow.comelse ( the left 4) then compare with above  , or right 4 also can compare above method...

ywl01

想了好久都不行

zhengfaxuezi

我的做法与4楼的做法一致，这样应该可以排除出来。但这个题目有个漏洞，只说重量异常，没说是重了，还是轻了。