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see xia da an
want to know
我来看看
check ans..
6 and 6 then 3 and 3 then 1 and 1
5識答?
thank you
将12个乒乓球分成平均两份,称一次
$ i) v2 k/ U6 i  _公仔箱論壇将比较重的那份再平均分成两份成一次os.tvboxnow.com( V8 ?. b! _8 N, u) u, e
剩下3个随意拿两个来称,如果天平平衡就是第三个,如果不平衡就是重的那个
thank
Thanks!
第一次系一边四个,一边四个秤既
1 - compare 4 with 49 [- y& z2 y8 N: B
if  (4v4)= same that means the rest of 4 is got more weighttvb now,tvbnow,bttvb7 G  [4 w7 @5 [  e# t
    then goto 2 - compare rest of(4)  - 2 with 2
6 ~  ~3 C1 f4 h           if (left side is more weight)
' L( o+ b$ J" O" G* |' E  ?公仔箱論壇              then goto 3 - compare last (left side of ( 2) - 1 with 1 => get answer
; }  {8 K& R/ [. [: r          else ( right side is more weight)os.tvboxnow.com& [# H5 z: j6 q3 \2 y) y. k+ k
              then goto 3 - compare last (right side of (2) - 1 with 1 => get answeros.tvboxnow.com% {+ X. R; A; f* ^9 I5 K
else ( the left 4) then compare with above  , or right 4 also can compare above method...
想了好久都不行
我的做法与4楼的做法一致,这样应该可以排除出来。但这个题目有个漏洞,只说重量异常,没说是重了,还是轻了。
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