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回復 #1 MagicAndy 的帖子

i wan to know
thx.~
thank you for sharing
look at it
i noe de ans cauz 1 do b4 already ^^os.tvboxnow.com5 }; X1 [* t$ ?0 d5 P
1st u divide the ball into two group (i group 6 ball)os.tvboxnow.com$ m/ m9 {8 @& |1 o1 A% s3 y& Z) N& e
then 称 them c which side is the heavy tvb now,tvbnow,bttvb" d, B) ^! ^; o2 I' A9 Y
then use the heavy side divide into 3 group 1group contain 2 ball 称 the 1st n 2nd group if its balance use the 3th group os.tvboxnow.com2 N' R: o4 ~5 i
if not balance take the heavy and then
9 X" }8 @2 p1 q- a2 E3 g1 S5 ?take the heavy group divided into 2 group i group contain 1 ball than 称 it
& i  ^. G9 W: ?) E% C# j2 u$ J/ F公仔箱論壇than the heavy ball is the ball u wan

回復 #1 MagicAndy 的帖子

how??????????
Oh..i did the same way as the first answer~am i wrong??Let me check~:onion18:
分三次算的话,每次分四粒来算,意思说当有一边较重时,只需要随意将其中六粒拿出来就知道那一粒是异常的了:onion14: os.tvboxnow.com. V6 Y+ a/ ?  M( d
(不知各位知不知道小弟说的解答,因为小弟不擅长解说)
thx 4 sharing
顶......

回復 #1 MagicAndy 的帖子

顶.......
简单到。。分3份。。每份4个。。第一次称。。必然知道3份中哪份包括异常的。。第二次..把包括的那份2:2的称。。又知道异常的一边
. C; f! P4 h; l( `% E( x然后。。1:1。。就知道了··
看解答!!!!!!!!!!!!!!
cccccc
idk..show me
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