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回復 #1 MagicAndy 的帖子

i wan to know
thx.~
thank you for sharing
look at it
i noe de ans cauz 1 do b4 already ^^
$ M3 T, j  B# W; Cos.tvboxnow.com1st u divide the ball into two group (i group 6 ball)
7 j' N$ ~0 r. |tvb now,tvbnow,bttvbthen 称 them c which side is the heavy 公仔箱論壇6 m* x" Q* `$ e$ K
then use the heavy side divide into 3 group 1group contain 2 ball 称 the 1st n 2nd group if its balance use the 3th group - a9 Y' ~: b" d. u$ Y- s! v7 b
if not balance take the heavy and then tvb now,tvbnow,bttvb+ U# y+ U; P9 k* n" J) d
take the heavy group divided into 2 group i group contain 1 ball than 称 it
: f, P* U( _/ @8 q公仔箱論壇than the heavy ball is the ball u wan

回復 #1 MagicAndy 的帖子

how??????????
Oh..i did the same way as the first answer~am i wrong??Let me check~:onion18:
分三次算的话,每次分四粒来算,意思说当有一边较重时,只需要随意将其中六粒拿出来就知道那一粒是异常的了:onion14: tvb now,tvbnow,bttvb7 [& l& P7 {5 ~. s# h5 u
(不知各位知不知道小弟说的解答,因为小弟不擅长解说)
thx 4 sharing
顶......

回復 #1 MagicAndy 的帖子

顶.......
简单到。。分3份。。每份4个。。第一次称。。必然知道3份中哪份包括异常的。。第二次..把包括的那份2:2的称。。又知道异常的一边tvb now,tvbnow,bttvb0 O* b: H( X/ ^! I
然后。。1:1。。就知道了··
看解答!!!!!!!!!!!!!!
cccccc
idk..show me
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