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答案!!!!!!!!!答案!!!!!!!!!!!答案!!!!!!!!!!!!!1
^:)^ >:D<
thx
let cc
not possible
不知道要怎麼做阿??
hao

the model answer is stupid

there got more simple way to do it, just read my way, the one i answered before
the
see 了
第一次,一边5个称,若质量没有异常就只称剩下的2个就知道异常的那个了;若有异常就把异常的那5个用一边2个称第二次,若没有异常就是剩下的那个异常了,若有异常就把异常的那2个再2一边1个称第三次就知道了
how?
先分3个一堆
* S# J: |  `1 ~8 r共四堆
1 T. s: q3 U; q$ C" G0 ntvb now,tvbnow,bttvb称两次得出异常的在那一堆,其轻重
7 M! G+ _& C) }7 R4 j在异常的那一堆中在称一次公仔箱論壇# R8 `, K% p( f% j  Z) B
就可以找到了
divde the 12 balls into 3 sets of 4. os.tvboxnow.com2 E0 p$ G, O6 ^
weight any 2 sets.) \% P/ H7 c' c2 X4 M% f2 ^  R
if the 2 sets are equal, then you know the heavy one is in the thirdtvb now,tvbnow,bttvb% ~7 s6 L7 S" D* R2 {; {+ K
if one of the 2 is heavier, then the heavy one is in that set公仔箱論壇: R, y8 @1 W1 n& `7 g
then divide the 4 balls into 2.2 X$ N( y4 ~& V6 x  Q) V/ [: ]/ |: \
weigh them
+ w4 c1 S/ T' T5 V0 k7 C' @tvb now,tvbnow,bttvband divide the heavier into 1
/ B" [1 }2 M6 Q1 q1 y0 Hos.tvboxnow.comand weight them.
: m# O" l6 b& M6 I5 Pos.tvboxnow.com3 x weighing and get the ans.  
. _: A; ^2 S& nos.tvboxnow.comin less than 15 secs.
1. 6 aside and weight.
  U) h% y9 P; M7 q" r2. heavier side from (1), 3 aside weight again.
+ F" g# |1 y: W$ K* h* _- R* ^* X9 ~" C3. heavier side from (2), take 2 out of 3 to weight. If equal weight the one not on the scale is the heavier one. else the heavier one on the scale is the odd one.
2 S7 L9 i& [6 O2 Q6 N& R3 Ttvb now,tvbnow,bttvb% I+ c4 O) J7 \# n
but i have a question. 重量異常 can be heavier or lighter.... so......
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