twinsdragon

That is a very simple mathematics question.
  `, B+ s3 H+ A8 qLet x = Male, y = Female, z = Childos.tvboxnow.com/ }/ F/ m1 @  ~$ r/ X& v' \
6x + 3y + z/2 = 100   Formula 1
- b* d. M+ U6 S! k* A2 k9 gx + y + z = 100    Formula 2
- L" t1 }) i: E2 N1 N( R公仔箱論壇Simplify Formula 2 into z, we get z = 100 - x - y Formula 3
4 G' x6 I# b2 ~4 B1 |. @Sub Formula 3 into Formula 1, we get 6x + 3y + ( 100 - x - y )/2 = 100 Formula 4
) R8 e9 z0 ], t3 S% d( Los.tvboxnow.comFormula 4 can change into 11x + 5y = 100 Formula 5
2 q! \2 f# a- o# m6 G4 @" \In Formula 5, x can only be 0 - 9, otherwise y will be negative number which we dont want.TVBNOW 含有熱門話題，最新最快電視，軟體，遊戲，電影，動漫及日常生活及興趣交流等資訊。: ?1 n. ^+ |8 E7 Z
And between 0 and 9, only 0 can give me a single number of y. So, x has to be 0 and y have to be 20. Then put x and y back to formula 1, we get z = 80.6 ?) X+ r& p& U3 [
Eventually, the answer is 20 female and 80 children and no male.