put six on each side firstos.tvboxnow.com; u# c* n5 B% [
1 [* \* K* K2 P9 rfrom the heavier six, split it to three on each sideos.tvboxnow.com( ]4 S5 b1 U# D4 {( E# Y
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then there is three left, put one on each side, if one is heavier then that is it, if they are balanced then last one is heavy one |