put six on each side firsttvb now,tvbnow,bttvb% G" y, a) ~1 [9 B8 L: Q9 H
9 A/ b9 ~. q( i Q% u
from the heavier six, split it to three on each side
% T( Z4 f4 S2 W1 {0 C5 h6 k, @+ J; S7 R; K
then there is three left, put one on each side, if one is heavier then that is it, if they are balanced then last one is heavy one |