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答案!!!!!!!!!答案!!!!!!!!!!!答案!!!!!!!!!!!!!1
^:)^ >:D<
thx
let cc
not possible
不知道要怎麼做阿??
hao

the model answer is stupid

there got more simple way to do it, just read my way, the one i answered before
the
see 了
第一次,一边5个称,若质量没有异常就只称剩下的2个就知道异常的那个了;若有异常就把异常的那5个用一边2个称第二次,若没有异常就是剩下的那个异常了,若有异常就把异常的那2个再2一边1个称第三次就知道了
how?
先分3个一堆公仔箱論壇2 E! m5 m8 x0 V
共四堆3 ~* e/ @: x+ S$ z) h
称两次得出异常的在那一堆,其轻重tvb now,tvbnow,bttvb" W8 k5 K3 I( o+ R; g# `* o
在异常的那一堆中在称一次TVBNOW 含有熱門話題,最新最快電視,軟體,遊戲,電影,動漫及日常生活及興趣交流等資訊。6 z* K$ @' D) n$ i
就可以找到了
divde the 12 balls into 3 sets of 4.
8 Z2 R! d$ x; Q  J; w. y/ hweight any 2 sets.
0 i( B9 P- ~  j) Y' Zif the 2 sets are equal, then you know the heavy one is in the third公仔箱論壇0 \4 K8 Q5 \! d! f, Y
if one of the 2 is heavier, then the heavy one is in that settvb now,tvbnow,bttvb9 s8 p- k+ ]7 K- |
then divide the 4 balls into 2.os.tvboxnow.com. h* Y# L9 T4 ^
weigh themos.tvboxnow.com& M+ T+ U3 V% Q. Y! U
and divide the heavier into 1os.tvboxnow.com& ~7 o" g* n0 \7 i1 |
and weight them.
1 e# l. `2 f1 s3 G. }* r3 x weighing and get the ans.  
; V3 T# a1 g$ N, Atvb now,tvbnow,bttvbin less than 15 secs.
1. 6 aside and weight.4 g; L, j  O0 q
2. heavier side from (1), 3 aside weight again.tvb now,tvbnow,bttvb3 G. c; m. u: h5 `1 Z) ~7 I9 q# `5 w
3. heavier side from (2), take 2 out of 3 to weight. If equal weight the one not on the scale is the heavier one. else the heavier one on the scale is the odd one.
) z7 J. E6 h0 ]3 vtvb now,tvbnow,bttvb
! [3 P; \9 M& B/ ]" V; r9 fos.tvboxnow.combut i have a question. 重量異常 can be heavier or lighter.... so......
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