zzzhao

see xia da an

yaukinman

want to know

zb7803

我来看看

lkhlewis

青蓮居士

check ans..

mkl2345

6 and 6 then 3 and 3 then 1 and 1

gg2968

5識答？

pyhzf

thank you

XYZCrux

将12个乒乓球分成平均两份，称一次# b. @3 Q+ `- T# b2 I3 }7 }% P
将比较重的那份再平均分成两份成一次
/ T$ s# L) P# P2 t/ C- t/ e剩下3个随意拿两个来称，如果天平平衡就是第三个，如果不平衡就是重的那个

wtfka

thank

agnesium

Thanks!

ban0212

第一次系一边四个，一边四个秤既

westgun

1 - compare 4 with 4+ w9 G) M: [7 {) j+ f3 Q
if  (4v4)= same that means the rest of 4 is got more weight, R: I% g2 f* f0 h. c# ^* f
    then goto 2 - compare rest of(4)  - 2 with 2
2 Q& A6 [' m* s. `2 n$ i" I1 ]           if (left side is more weight)
, a7 ?( v. D& R" p, qos.tvboxnow.com              then goto 3 - compare last (left side of ( 2) - 1 with 1 => get answer8 F4 {* S  K0 Z5 s- M
          else ( right side is more weight)4 y# r' K0 X7 j$ D
              then goto 3 - compare last (right side of (2) - 1 with 1 => get answertvb now,tvbnow,bttvb+ R/ p: a/ P& M
else ( the left 4) then compare with above  , or right 4 also can compare above method...

ywl01

想了好久都不行

zhengfaxuezi

我的做法与4楼的做法一致，这样应该可以排除出来。但这个题目有个漏洞，只说重量异常，没说是重了，还是轻了。