hoeteck

i wan to know

wenlove08

thx.~

caseylee0427

thank you for sharing

rock5356466

look at it

leo_04236

i noe de ans cauz 1 do b4 already ^^公仔箱論壇8 I9 `* m+ o9 k
1st u divide the ball into two group (i group 6 ball)公仔箱論壇9 q1 F# b( N2 r
then 称 them c which side is the heavy tvb now,tvbnow,bttvb0 _- z& |0 T1 R7 b! N* M: S4 t: Y
then use the heavy side divide into 3 group 1group contain 2 ball 称 the 1st n 2nd group if its balance use the 3th group
8 w( ~+ \$ G* s" V5 j公仔箱論壇if not balance take the heavy and then
/ B7 h0 Q7 J& v* n; Dtake the heavy group divided into 2 group i group contain 1 ball than 称 it ( r8 `+ S: }1 M9 d
than the heavy ball is the ball u wan

sam5881

how??????????

ar_yuo

Oh..i did the same way as the first answer~am i wrong??Let me check~:onion18:

单身汉

分三次算的话，每次分四粒来算，意思说当有一边较重时，只需要随意将其中六粒拿出来就知道那一粒是异常的了:onion14: os.tvboxnow.com' B+ m5 Z& `) _0 M
（不知各位知不知道小弟说的解答，因为小弟不擅长解说）

ldcloud

thx 4 sharing

烟灰缸

顶．．．．．．

烟灰缸

顶．．．．．．．

haharinny

简单到。。分3份。。每份4个。。第一次称。。必然知道3份中哪份包括异常的。。第二次..把包括的那份2：2的称。。又知道异常的一边
/ A, Y7 V! J* q8 X5 N" Q2 r4 W9 G公仔箱論壇然后。。1：1。。就知道了··

htq771112

看解答!!!!!!!!!!!!!!

puki

cccccc

Hikouseki

idk..show me