1 1 1, because any number can have factor of 1. also, only 1 can be true if any random number multiple plus has to be divided by the remaining digit. So, 1 1 1 is my answer.
They would be 111 or 123& A1 f! J+ [3 V
For 111 would be 1x1+1=2 that is 2 times of 3rd 1 - V. @- B- J2 a. Q! m+ \TVBNOW 含有熱門話題，最新最快電視，軟體，遊戲，電影，動漫及日常生活及興趣交流等資訊。For 123 9 K; Q- x3 j( C, T: Y/ BTVBNOW 含有熱門話題，最新最快電視，軟體，遊戲，電影，動漫及日常生活及興趣交流等資訊。1x2+1=3 that is 1 time of 38 R3 z& v7 d$ W3 i6 Z @; b
1x3+1=4 that is 2 times of 2 ' k3 y* u" T" w+ K$ }- K/ J$ h1 }2x3+1=7 thta is 7 times of 1
發表於 2009-8-19 02:33 PM
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