That is a very simple mathematics question.公仔箱論壇& r c3 c+ b! l$ V2 v3 L& u
Let x = Male, y = Female, z = Child公仔箱論壇, z+ J# E0 K' I9 N
6x + 3y + z/2 = 100 Formula 1tvb now,tvbnow,bttvb, e4 W: n. l9 U& p5 H
x + y + z = 100 Formula 2
/ Z& Y& R/ F: x }" u3 ]公仔箱論壇Simplify Formula 2 into z, we get z = 100 - x - y Formula 3os.tvboxnow.com0 X; z; Y) g+ L7 E8 W0 A# _
Sub Formula 3 into Formula 1, we get 6x + 3y + ( 100 - x - y )/2 = 100 Formula 4
2 j8 i; ]& B3 kFormula 4 can change into 11x + 5y = 100 Formula 5
" w ]8 q! ~& [7 @5 L" B q9 nos.tvboxnow.comIn Formula 5, x can only be 0 - 9, otherwise y will be negative number which we dont want.os.tvboxnow.com% y, i: F9 V8 f E9 Z
And between 0 and 9, only 0 can give me a single number of y. So, x has to be 0 and y have to be 20. Then put x and y back to formula 1, we get z = 80.) y' m/ h [* w, t( H: b
Eventually, the answer is 20 female and 80 children and no male. |