1. divide 6 and 6, both sides will not equal $ o; u6 B" y" N. P# U, k) I3 p( r2. take any side of the 6, divide then 3 and 3, again both sides will not equal + h; }+ |; g( J0 e2 s3. take any 2 and weigh themtvb now,tvbnow,bttvb% y3 j- w& ~6 g6 I0 j7 |
if they equal, the one left is the ball.