put six on each side first b0 T* X: N! p
tvb now,tvbnow,bttvb& d, z$ j0 U) _0 w) j' S
from the heavier six, split it to three on each sidetvb now,tvbnow,bttvb1 g: h* T O- M; t
tvb now,tvbnow,bttvb+ K1 ^, W% L- J5 a
then there is three left, put one on each side, if one is heavier then that is it, if they are balanced then last one is heavy one |