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回復 #1 MagicAndy 的帖子

i wan to know
thx.~
thank you for sharing
look at it
i noe de ans cauz 1 do b4 already ^^
: q' [1 o" \; }3 R0 [os.tvboxnow.com1st u divide the ball into two group (i group 6 ball)
) v8 p% l8 u- y3 w' `& j4 kos.tvboxnow.comthen 称 them c which side is the heavy
5 X3 v6 R6 B7 ^. Z( h% Sos.tvboxnow.comthen use the heavy side divide into 3 group 1group contain 2 ball 称 the 1st n 2nd group if its balance use the 3th group os.tvboxnow.com! W, p6 W+ p8 ~4 M
if not balance take the heavy and then # H3 E/ k5 L) s
take the heavy group divided into 2 group i group contain 1 ball than 称 it
5 h! D" [2 _% A* m' O4 [) jtvb now,tvbnow,bttvbthan the heavy ball is the ball u wan

回復 #1 MagicAndy 的帖子

how??????????
Oh..i did the same way as the first answer~am i wrong??Let me check~:onion18:
分三次算的话,每次分四粒来算,意思说当有一边较重时,只需要随意将其中六粒拿出来就知道那一粒是异常的了:onion14: TVBNOW 含有熱門話題,最新最快電視,軟體,遊戲,電影,動漫及日常生活及興趣交流等資訊。# A7 U, P: j, @4 x- W; N+ V/ i
(不知各位知不知道小弟说的解答,因为小弟不擅长解说)
thx 4 sharing
顶......

回復 #1 MagicAndy 的帖子

顶.......
简单到。。分3份。。每份4个。。第一次称。。必然知道3份中哪份包括异常的。。第二次..把包括的那份2:2的称。。又知道异常的一边os.tvboxnow.com6 A* }6 B6 |0 O) X
然后。。1:1。。就知道了··
看解答!!!!!!!!!!!!!!
cccccc
idk..show me
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