hoeteck

i wan to know

wenlove08

thx.~

caseylee0427

thank you for sharing

rock5356466

look at it

leo_04236

i noe de ans cauz 1 do b4 already ^^
8 n& M5 T$ m: V! P1st u divide the ball into two group (i group 6 ball)
, P$ X( C8 X2 D4 Zthen 称 them c which side is the heavy
' _4 [/ ]% U% r: t9 i( Ztvb now,tvbnow,bttvbthen use the heavy side divide into 3 group 1group contain 2 ball 称 the 1st n 2nd group if its balance use the 3th group 公仔箱論壇; _* I/ e+ ?+ k6 C5 R$ u
if not balance take the heavy and then ) Z. ?& X; E! x" k
take the heavy group divided into 2 group i group contain 1 ball than 称 it # X: B, b% C" O0 L- `
than the heavy ball is the ball u wan

sam5881

how??????????

ar_yuo

Oh..i did the same way as the first answer~am i wrong??Let me check~:onion18:

单身汉

分三次算的话，每次分四粒来算，意思说当有一边较重时，只需要随意将其中六粒拿出来就知道那一粒是异常的了:onion14: 公仔箱論壇8 v3 I$ p* B9 m2 `" }! D* D: C/ m
（不知各位知不知道小弟说的解答，因为小弟不擅长解说）

ldcloud

thx 4 sharing

烟灰缸

顶．．．．．．

烟灰缸

顶．．．．．．．

haharinny

简单到。。分3份。。每份4个。。第一次称。。必然知道3份中哪份包括异常的。。第二次..把包括的那份2：2的称。。又知道异常的一边
5 y! ?7 Q1 D9 M2 I! Q2 q然后。。1：1。。就知道了··

htq771112

看解答!!!!!!!!!!!!!!

puki

cccccc

Hikouseki

idk..show me