The best chance is #3 because all he needs is take #1 + #2 divide by 2. e.g. #1+#2=28 then he take 14. This is the best chance to avoid being highest or lowest and worst case scenario is he equals #1 & #2. However because all 5 knows this simple theory so I think they all died because they all ended up picking the same number of beans.
2 n$ \( R$ b4 q' T9 Otvb now,tvbnow,bttvb
8 L; ~! a9 S* T: t& |6 f. s6 itvb now,tvbnow,bttvbStarting from #1, he knows he cannot pick anything bigger then 49 because if he did, then #2 only have to leave 3 beans for #3 #4 & #5 then he'll live. e.g. #1 picked 53 then #2 picks 100-53-3=44. then A,C,D,E all died. e.g. #1=53, #2=(100-53-3)=44, #3=1, #4=1, #5=1. The best chance for #1 is to pick anything less then or equal the median 20 (100 divided by 5). In fact anything between 3-20 won't change the result. Let's say #1 pick 20.
3 t- g8 g- L5 C: O* W. o* q$ v公仔箱論壇
/ Q& _& ]" G9 Q, q# e5 {tvb now,tvbnow,bttvbNow #2 knows whatever he picks, #3 will take the median between him & #1 e.g. now #1 picked 20, if he pick 6 then #3 will pick 13 putting him either being the lowest or highest. He cannot allow that so the best chance is to match #1, so he picked 20 as well.公仔箱論壇, X( H: e0 T/ U) ]' K' P; l0 v
P, p, u/ O; r; F% z7 e4 STVBNOW 含有熱門話題，最新最快電視，軟體，遊戲，電影，動漫及日常生活及興趣交流等資訊。#3 did the obvious choice 40 divided by 2 =20, so he picked 20 S: t4 _7 a1 r& @* u: T# @, a
# C% h, ^ X- Q; v) Z7 S! M+ R#4 base on knowing the median rule take 60 divided by 3 =20, so he picked 20 as well.
& l4 I. L8 K* X4 O2 g) H: t公仔箱論壇
& c- @- @0 L2 b5 s2 Itvb now,tvbnow,bttvb#5 same as above, he takes 80 divided by 4 =20, picked 20 as well.tvb now,tvbnow,bttvb) S2 B3 q9 t6 \2 c& p) h
% G$ T4 R0 w( A5 m4 T* v5 yTVBNOW 含有熱門話題，最新最快電視，軟體，遊戲，電影，動漫及日常生活及興趣交流等資訊。Ended all have the same number and all died. |
發表於 2006-12-9 12:41 AM
| 
os.tvboxnow.com; h3 _7 f# O" t* G
