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第2的....直覺告訴我
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友華
我已經想很久了tvb now,tvbnow,bttvb/ Q; l; g9 `2 a( n
實在太難公仔箱論壇' R" P! N9 ^( a: o3 m8 J
只好來看答案了
no2,,3,4應該沒那麼容易死瓜

回復第 1 帖由 蘭昀 所發的帖子

number 4 has the best chance to live# ]) e) z0 ?9 ~" k& Z* b% P
assume number 1, 2, 3 and 4, pick number a, b, c and d.$ C: U% \" O: J
number 4 knows how many left in the bag which is 100-a-b-c, Q# h4 D; o  B5 l, m/ Q
take the average of (100-a-b-c)
5 n3 P$ H! n$ f( w2 xthen number 4 knows a or b or c must be greater or less than average of (100-a-b-c)公仔箱論壇0 \' F; L" S) |  l9 F$ z4 k2 y
and number 4 can squeeze himself into the average and what number 5 picks.
1 ?. [! U2 H3 `" p  Y- X公仔箱論壇so number 4 will have the best chance.os.tvboxnow.com! L6 j5 r* U8 g

$ l: p. w$ a  m( v& y. R- a公仔箱論壇i hope this is a good logic hehe
同意楼上 Number 4 係最安全!! Number5 係一定死咖了!! 不过我就唔知 Number 1,2,3 边个唔好彩jie !!
$ _4 a. i1 O2 x( @! i! g( a玩心理咖话!! 5号 好大压力!! 因为就算佢知剩下几多豆 佢豆好难判断所以!!!tvb now,tvbnow,bttvb: ]- G( f2 h$ r# g/ e0 z0 C

  S- t0 u! o% G+ F  d公仔箱論壇如果绝D咖哇!!  全部豆色!!! 1号摞97粒 剩下3粒 一人一粒  大家一锅熟 哈哈!!!!(因为一人要一粒 所以佢哋冇得拣  只可以摞一粒!!)
想不到!!答案呢?
應該是第三ㄍ吧
no 2 !!! no 2 !!!                   ; D2 D. O) P  [' n

$ u/ b2 I& x$ C( \8 gos.tvboxnow.com             no 1 take 20 ( can be any ) no 2 take 19 ( can be any ) , no 3, 4, 5, take 18, 18, 18.
# z9 ~0 {+ e  w, a+ E. B公仔箱論壇So they will all die !!                                                      
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2 i% l& `  G) f& J/ F$ q公仔箱論壇
2 L* D+ N+ [; f) h) l- h4 c! wtvb now,tvbnow,bttvbos.tvboxnow.com5 E  x1 \, y+ S5 B( I' l) o
公仔箱論壇- S7 r9 p* l! s4 u

5 i- O: b0 ~/ b0 O6 UJust Joking !!!
The best chance is #3 because all he needs is take #1 + #2 divide by 2. e.g. #1+#2=28 then he take 14. This is the best chance to avoid being highest or lowest and worst case scenario is he equals #1 & #2. However because all 5 knows this simple theory so I think they all died because they all ended up picking the same number of beans.' `. ?+ U: K8 h* b
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Starting from #1, he knows he cannot pick anything bigger then 49 because if he did, then #2 only have to leave 3 beans for #3 #4 & #5 then he'll live. e.g. #1 picked 53 then #2 picks 100-53-3=44.  then A,C,D,E all died. e.g. #1=53, #2=(100-53-3)=44, #3=1, #4=1, #5=1. The best chance for #1 is to pick anything less then or equal the median 20 (100 divided by 5). In fact anything between 3-20 won't change the result. Let's say #1 pick 20.  公仔箱論壇7 G2 W9 Y+ F' x
os.tvboxnow.com! N$ \4 I1 B: D0 q6 o& T
Now #2 knows whatever he picks, #3 will take the median between him & #1 e.g. now #1 picked 20, if he pick 6 then #3 will pick 13 putting him either being the lowest or highest. He cannot allow that so the best chance is to match #1, so he picked 20 as well.TVBNOW 含有熱門話題,最新最快電視,軟體,遊戲,電影,動漫及日常生活及興趣交流等資訊。- z7 g; q& [% Y1 X! i

1 P/ v+ S! N$ J5 @tvb now,tvbnow,bttvb#3 did the obvious choice 40 divided by 2 =20, so he picked 20
4 }; X# V$ J2 \6 H1 B2 |3 dos.tvboxnow.comos.tvboxnow.com6 k2 a9 e$ O( Q. N- \( ~
#4 base on knowing the median rule take 60 divided by 3 =20, so he picked 20 as well.8 `, _" C% C& n, [4 B
tvb now,tvbnow,bttvb5 R1 C. ]1 }8 @5 s/ a
#5 same as above, he takes 80 divided by 4 =20, picked 20 as well.
5 L, i; K: k- ~( h% L* Z1 X5 OTVBNOW 含有熱門話題,最新最快電視,軟體,遊戲,電影,動漫及日常生活及興趣交流等資訊。0 b6 f9 X& @, ]) @4 y8 g5 B% r
Ended all have the same number and all died.
我猜NO4,TVBNOW 含有熱門話題,最新最快電視,軟體,遊戲,電影,動漫及日常生活及興趣交流等資訊。% h' P$ i& w/ a
因為他可以取前面三位豆子的平均數,
* s  c  ]! U! d, _公仔箱論壇也可以防止豆子不夠讓NO5墊底。
最后一个人最安全!因为当四个人拿完之后,他可以拿quarter of 之前拿的总数,咁样嘅话,佢係最大或者最小的几率係最低嘅```而前面几个人,用呢种方法摞会係最大或者最小的几率会比5号大D...而呢种方法係最有效避免最大或者最小嘅
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" x% l: W6 q8 n9 _' Q' R/ Q" F# \os.tvboxnow.com[ 本帖最後由 289675283 於 2006-12-15 01:21 AM 編輯 ]
[-X  所謂IQ題唔喺可以用普通思維gē,TVBNOW 含有熱門話題,最新最快電視,軟體,遊戲,電影,動漫及日常生活及興趣交流等資訊。  Z3 D- r: \5 G. ?: I
os.tvboxnow.com/ G( C  b. q  m
答案應該喺 :抓豆子不多不少的那個囚犯存活率是最大的
想想
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