1. divide 6 and 6, both sides will not equal- V( u/ Q! o! c! W
2. take any side of the 6, divide then 3 and 3, again both sides will not equal ' i7 }! l1 V _ X% |: s# t( ptvb now,tvbnow,bttvb3. take any 2 and weigh themtvb now,tvbnow,bttvb% m# o7 z9 v7 f1 k, H5 [8 ^' i9 F
if they equal, the one left is the ball.