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答案!!!!!!!!!答案!!!!!!!!!!!答案!!!!!!!!!!!!!1
^:)^ >:D<
thx
let cc
not possible
不知道要怎麼做阿??
hao

the model answer is stupid

there got more simple way to do it, just read my way, the one i answered before
the
see 了
第一次,一边5个称,若质量没有异常就只称剩下的2个就知道异常的那个了;若有异常就把异常的那5个用一边2个称第二次,若没有异常就是剩下的那个异常了,若有异常就把异常的那2个再2一边1个称第三次就知道了
how?
先分3个一堆" y4 i, Q5 K0 T. l
共四堆
4 ~7 C5 K7 C1 w2 f) f' o9 ?称两次得出异常的在那一堆,其轻重
+ p/ E; t: w$ S9 t- {os.tvboxnow.com在异常的那一堆中在称一次tvb now,tvbnow,bttvb- C# c9 F, v$ s
就可以找到了
divde the 12 balls into 3 sets of 4.
) }1 s0 x3 @5 [! _$ ^, m) U9 Rweight any 2 sets.1 l, e7 w, m1 q- f9 Q
if the 2 sets are equal, then you know the heavy one is in the third
- o3 b- e, Y6 a! mTVBNOW 含有熱門話題,最新最快電視,軟體,遊戲,電影,動漫及日常生活及興趣交流等資訊。if one of the 2 is heavier, then the heavy one is in that setTVBNOW 含有熱門話題,最新最快電視,軟體,遊戲,電影,動漫及日常生活及興趣交流等資訊。' l+ \+ W$ G# T6 S& v
then divide the 4 balls into 2.os.tvboxnow.com" f: F6 b: e- c; p$ c
weigh them
$ X' X+ ~9 x$ C- r公仔箱論壇and divide the heavier into 1公仔箱論壇# T, S! a( n' ?. R
and weight them.
; t) ~, u' W3 F% g7 _3 x weighing and get the ans.  TVBNOW 含有熱門話題,最新最快電視,軟體,遊戲,電影,動漫及日常生活及興趣交流等資訊。$ u( r" T9 Y  K' ?; j4 z
in less than 15 secs.
1. 6 aside and weight.. n. g) u' j6 t! t; Y6 N
2. heavier side from (1), 3 aside weight again.  C6 s8 h- |" c; Y
3. heavier side from (2), take 2 out of 3 to weight. If equal weight the one not on the scale is the heavier one. else the heavier one on the scale is the odd one. tvb now,tvbnow,bttvb# }1 p# s; I  X8 j- K- _

1 v6 Z; s9 Y, y) etvb now,tvbnow,bttvbbut i have a question. 重量異常 can be heavier or lighter.... so......
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