hoeteck

i wan to know

wenlove08

thx.~

caseylee0427

thank you for sharing

rock5356466

look at it

leo_04236

i noe de ans cauz 1 do b4 already ^^
: C' w" V7 m  vtvb now,tvbnow,bttvb1st u divide the ball into two group (i group 6 ball)公仔箱論壇% H0 V8 N  b( _5 Z9 C$ A& }
then 称 them c which side is the heavy
  S. F: R% C/ h6 L! b* pthen use the heavy side divide into 3 group 1group contain 2 ball 称 the 1st n 2nd group if its balance use the 3th group os.tvboxnow.com* j5 S, f4 E4 C* V6 p7 @# Q
if not balance take the heavy and then / t5 W- k2 Z0 I  t3 N  n
take the heavy group divided into 2 group i group contain 1 ball than 称 it os.tvboxnow.com8 c5 ]8 K6 j) z  F4 }. |3 z% G
than the heavy ball is the ball u wan

sam5881

how??????????

ar_yuo

Oh..i did the same way as the first answer~am i wrong??Let me check~:onion18:

单身汉

分三次算的话，每次分四粒来算，意思说当有一边较重时，只需要随意将其中六粒拿出来就知道那一粒是异常的了:onion14: tvb now,tvbnow,bttvb0 R4 w! G) {2 k- o' @5 C
（不知各位知不知道小弟说的解答，因为小弟不擅长解说）

ldcloud

thx 4 sharing

烟灰缸

顶．．．．．．

烟灰缸

顶．．．．．．．

haharinny

简单到。。分3份。。每份4个。。第一次称。。必然知道3份中哪份包括异常的。。第二次..把包括的那份2：2的称。。又知道异常的一边
. z2 y5 E0 x1 M  e0 c# e0 R然后。。1：1。。就知道了··

htq771112

看解答!!!!!!!!!!!!!!

puki

cccccc

Hikouseki

idk..show me