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回復 #1 MagicAndy 的帖子

i wan to know
thx.~
thank you for sharing
look at it
i noe de ans cauz 1 do b4 already ^^公仔箱論壇3 X$ c. `0 Y' s. L4 ?; U$ v
1st u divide the ball into two group (i group 6 ball)
4 t) ~' V  a  P* sthen 称 them c which side is the heavy
3 X/ h5 c7 u' S9 Dos.tvboxnow.comthen use the heavy side divide into 3 group 1group contain 2 ball 称 the 1st n 2nd group if its balance use the 3th group
$ l: E3 D3 f4 E4 W1 u9 `4 Qtvb now,tvbnow,bttvbif not balance take the heavy and then tvb now,tvbnow,bttvb. u% @# ]5 h2 r$ ^) `
take the heavy group divided into 2 group i group contain 1 ball than 称 it 5 o* n3 M2 {7 j2 T* x  H5 q
than the heavy ball is the ball u wan

回復 #1 MagicAndy 的帖子

how??????????
Oh..i did the same way as the first answer~am i wrong??Let me check~:onion18:
分三次算的话,每次分四粒来算,意思说当有一边较重时,只需要随意将其中六粒拿出来就知道那一粒是异常的了:onion14: & }! E# ~; g% @0 E* Z
(不知各位知不知道小弟说的解答,因为小弟不擅长解说)
thx 4 sharing
顶......

回復 #1 MagicAndy 的帖子

顶.......
简单到。。分3份。。每份4个。。第一次称。。必然知道3份中哪份包括异常的。。第二次..把包括的那份2:2的称。。又知道异常的一边os.tvboxnow.com- e/ }$ A/ q) n" {* l
然后。。1:1。。就知道了··
看解答!!!!!!!!!!!!!!
cccccc
idk..show me
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