hoeteck

i wan to know

wenlove08

thx.~

caseylee0427

thank you for sharing

rock5356466

look at it

leo_04236

i noe de ans cauz 1 do b4 already ^^tvb now,tvbnow,bttvb+ g0 a1 d  E9 R8 b- ]! ?3 n6 b
1st u divide the ball into two group (i group 6 ball)os.tvboxnow.com7 j& J( V, ?& i0 y& l
then 称 them c which side is the heavy 2 `; I' R0 y$ J6 f$ A7 r- ?
then use the heavy side divide into 3 group 1group contain 2 ball 称 the 1st n 2nd group if its balance use the 3th group 1 C  M' n1 t! M$ a: c* l9 P
if not balance take the heavy and then , l) ~% f2 g( d2 C' ~5 h1 I+ _
take the heavy group divided into 2 group i group contain 1 ball than 称 it ; x' f0 r4 N' B  ^# s" h1 J! Y4 U
than the heavy ball is the ball u wan

sam5881

how??????????

ar_yuo

Oh..i did the same way as the first answer~am i wrong??Let me check~:onion18:

单身汉

分三次算的话，每次分四粒来算，意思说当有一边较重时，只需要随意将其中六粒拿出来就知道那一粒是异常的了:onion14: 0 O) O0 \) U, B- W0 r3 O
（不知各位知不知道小弟说的解答，因为小弟不擅长解说）

ldcloud

thx 4 sharing

烟灰缸

顶．．．．．．

烟灰缸

顶．．．．．．．

haharinny

简单到。。分3份。。每份4个。。第一次称。。必然知道3份中哪份包括异常的。。第二次..把包括的那份2：2的称。。又知道异常的一边
0 Y) H+ v( E1 `" f- E然后。。1：1。。就知道了··

htq771112

看解答!!!!!!!!!!!!!!

puki

cccccc

Hikouseki

idk..show me