zozozoo

直接看答案！

chungary919

i find one solution that is similar
: P/ a: A3 r5 t4 {but i can't specify the heavier one is abnormal or the lighter one is abnormal when the case that has only two balls left....tvb now,tvbnow,bttvb  R# a4 \# _1 T' u" j! P
maybe there is a better one, let me see sin

chungary919

it is already good IQ if you can understand the answer......

bbbnd

pretty difficult... needa see answer

yind

!!!!!!!!!!!!!!!!!!!!!!!!!

jyllc999

444公仔箱論壇9 d0 }9 O' p- G
22TVBNOW 含有熱門話題，最新最快電視，軟體，遊戲，電影，動漫及日常生活及興趣交流等資訊。+ k0 K: V0 }3 }7 o% ^% ^3 ~4 Z
11

jimmy5943

thanks for share:onion14:

lam7780

is that really possible, i want to know

cruzi

interesting ...

chlOe~~x

.... thx for sharing !

paddyleejun

ddddd

i761120

actually this question always have someone asked, the calculation is very complicated, should give a no. of each ball, and first weight it in 6-6, and .... forgot...

kelvinmok85

how oh???

counterpain

Let me see the answer