number 4 has the best chance to liveos.tvboxnow.com! ]/ j n' m5 `! c0 l: u
assume number 1, 2, 3 and 4, pick number a, b, c and d.
2 i: T9 ^; N- e+ P% G2 Y; {) ?number 4 knows how many left in the bag which is 100-a-b-c
: K( s2 c/ @, ?" \$ Ytvb now,tvbnow,bttvbtake the average of (100-a-b-c)公仔箱論壇5 h1 c. ^4 ?, w3 t" }8 ?( ]
then number 4 knows a or b or c must be greater or less than average of (100-a-b-c)
4 ~. h0 m/ q$ c+ f# x" t$ ^+ @and number 4 can squeeze himself into the average and what number 5 picks.tvb now,tvbnow,bttvb' e1 b: K" `' d0 X. F
so number 4 will have the best chance.
/ l7 D& l2 I! m2 b. ~. E; ytvb now,tvbnow,bttvbos.tvboxnow.com5 @0 x, T- T* Y. ~# Q/ V
i hope this is a good logic hehe |