loveallcar

number 4 has the best chance to live; @& s5 d% M# `& T# f; P9 `
assume number 1, 2, 3 and 4, pick number a, b, c and d.os.tvboxnow.com4 Z( h$ M5 u1 \: s1 s- M
number 4 knows how many left in the bag which is 100-a-b-c
* _, p, g2 G/ dtake the average of (100-a-b-c)公仔箱論壇. B" Q/ }/ v: m, N% Y  D
then number 4 knows a or b or c must be greater or less than average of (100-a-b-c)
8 K: a8 r. L1 U9 Y; }+ Htvb now,tvbnow,bttvband number 4 can squeeze himself into the average and what number 5 picks.
8 _) A4 l1 u5 T& w, lso number 4 will have the best chance.4 w5 u. \0 \0 u  f% H! [

9 d: l# R5 O+ R4 y7 O7 Z" Pi hope this is a good logic hehe

loveallcar

aiya, how come still no answer ga.tvb now,tvbnow,bttvb; W& ]  U9 H! t7 l
please post answer la
+ k( v$ }& o1 {7 Z2 D: f# l- D公仔箱論壇can't wait la