number 4 has the best chance to live) J* p3 ~9 u5 Z: z+ u: t- _7 e
assume number 1, 2, 3 and 4, pick number a, b, c and d.公仔箱論壇5 j T1 L5 w9 g9 U" N8 g" \
number 4 knows how many left in the bag which is 100-a-b-c( f# _' e0 s1 a9 t
take the average of (100-a-b-c)
2 @/ N5 A' W# Qthen number 4 knows a or b or c must be greater or less than average of (100-a-b-c)" c$ G& h& V+ `/ ?( ]% J
and number 4 can squeeze himself into the average and what number 5 picks.. Y, F" \) P9 V. E- x K
so number 4 will have the best chance.os.tvboxnow.com3 M. N) T4 t4 {2 f
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i hope this is a good logic hehe |