number 4 has the best chance to live
( G, `2 Z* w9 xos.tvboxnow.comassume number 1, 2, 3 and 4, pick number a, b, c and d./ ]. C2 J, ]. E
number 4 knows how many left in the bag which is 100-a-b-c
- ?2 q% q. ^$ ~公仔箱論壇take the average of (100-a-b-c)
7 B: c* T" E8 i+ t% r r: G: _os.tvboxnow.comthen number 4 knows a or b or c must be greater or less than average of (100-a-b-c)公仔箱論壇8 `5 D! W5 ?2 }6 ]
and number 4 can squeeze himself into the average and what number 5 picks.
9 q( o! A8 V+ t! o9 |: o公仔箱論壇so number 4 will have the best chance.
; }$ `5 O$ U9 _; X! X2 j
9 m% l i4 h ~7 k, @os.tvboxnow.comi hope this is a good logic hehe |
發表於 2006-12-12 09:29 AM
| 