The best chance is #3 because all he needs is take #1 + #2 divide by 2. e.g. #1+#2=28 then he take 14. This is the best chance to avoid being highest or lowest and worst case scenario is he equals #1 & #2. However because all 5 knows this simple theory so I think they all died because they all ended up picking the same number of beans.
) F, T* A; L: @, H* G P( m6 _# a+ fos.tvboxnow.com2 |! J2 f+ h' F% ?
Starting from #1, he knows he cannot pick anything bigger then 49 because if he did, then #2 only have to leave 3 beans for #3 #4 & #5 then he'll live. e.g. #1 picked 53 then #2 picks 100-53-3=44. then A,C,D,E all died. e.g. #1=53, #2=(100-53-3)=44, #3=1, #4=1, #5=1. The best chance for #1 is to pick anything less then or equal the median 20 (100 divided by 5). In fact anything between 3-20 won't change the result. Let's say #1 pick 20. 公仔箱論壇: Y+ L! B% N1 A& \: A% n8 c& Z
9 c9 ^) m+ V& S u# los.tvboxnow.comNow #2 knows whatever he picks, #3 will take the median between him & #1 e.g. now #1 picked 20, if he pick 6 then #3 will pick 13 putting him either being the lowest or highest. He cannot allow that so the best chance is to match #1, so he picked 20 as well.
, U% m7 `/ C/ z' ~& ?2 _' k ^! bos.tvboxnow.com公仔箱論壇: I c2 d1 n7 F! l5 ]$ ~
#3 did the obvious choice 40 divided by 2 =20, so he picked 20TVBNOW 含有熱門話題，最新最快電視，軟體，遊戲，電影，動漫及日常生活及興趣交流等資訊。- A7 k; v# i2 s) J
tvb now,tvbnow,bttvb& q( I+ @. A/ ^0 `& E6 z
#4 base on knowing the median rule take 60 divided by 3 =20, so he picked 20 as well.tvb now,tvbnow,bttvb' G U* h; v2 H
1 \: _. g0 C6 \0 w/ o3 Z公仔箱論壇#5 same as above, he takes 80 divided by 4 =20, picked 20 as well.
* D. p& S9 }* C' a# p* C2 X% V5 T: \os.tvboxnow.com6 ]' m- x% R. e
Ended all have the same number and all died. |
發表於 2006-12-9 12:41 AM
| 
3 |. }8 T' J& B. {& ]. W9 e+ [
