The best chance is #3 because all he needs is take #1 + #2 divide by 2. e.g. #1+#2=28 then he take 14. This is the best chance to avoid being highest or lowest and worst case scenario is he equals #1 & #2. However because all 5 knows this simple theory so I think they all died because they all ended up picking the same number of beans.
& U9 F$ ?" r6 r1 j/ htvb now,tvbnow,bttvb/ j5 ?4 r( `9 Q
Starting from #1, he knows he cannot pick anything bigger then 49 because if he did, then #2 only have to leave 3 beans for #3 #4 & #5 then he'll live. e.g. #1 picked 53 then #2 picks 100-53-3=44. then A,C,D,E all died. e.g. #1=53, #2=(100-53-3)=44, #3=1, #4=1, #5=1. The best chance for #1 is to pick anything less then or equal the median 20 (100 divided by 5). In fact anything between 3-20 won't change the result. Let's say #1 pick 20. TVBNOW 含有熱門話題，最新最快電視，軟體，遊戲，電影，動漫及日常生活及興趣交流等資訊。$ L. e% ?% e" {. |/ t) N
os.tvboxnow.com) A a. ~! }, B* t9 q1 C& n
Now #2 knows whatever he picks, #3 will take the median between him & #1 e.g. now #1 picked 20, if he pick 6 then #3 will pick 13 putting him either being the lowest or highest. He cannot allow that so the best chance is to match #1, so he picked 20 as well.
4 M7 }0 E* O% M8 h. ^tvb now,tvbnow,bttvb
" i* I* E1 u* D' j# q7 f6 D( OTVBNOW 含有熱門話題，最新最快電視，軟體，遊戲，電影，動漫及日常生活及興趣交流等資訊。#3 did the obvious choice 40 divided by 2 =20, so he picked 20
6 o8 R/ _* P Q! v; \
8 Z O" J/ ~. {6 ?#4 base on knowing the median rule take 60 divided by 3 =20, so he picked 20 as well., p, P# ^& S" R& x8 `* B4 X8 a
TVBNOW 含有熱門話題，最新最快電視，軟體，遊戲，電影，動漫及日常生活及興趣交流等資訊。7 K, I( \1 H. Z- w; E- m& e/ O# Q6 W
#5 same as above, he takes 80 divided by 4 =20, picked 20 as well.
# M t' X: |9 R1 D- G# \' P% lTVBNOW 含有熱門話題，最新最快電視，軟體，遊戲，電影，動漫及日常生活及興趣交流等資訊。
1 I! `" Q1 ?( g) V$ \os.tvboxnow.comEnded all have the same number and all died. |
發表於 2006-12-9 12:41 AM
| 
