The best chance is #3 because all he needs is take #1 + #2 divide by 2. e.g. #1+#2=28 then he take 14. This is the best chance to avoid being highest or lowest and worst case scenario is he equals #1 & #2. However because all 5 knows this simple theory so I think they all died because they all ended up picking the same number of beans.公仔箱論壇; l! M. G- O: |9 c$ G+ j
; e3 b8 e3 y( [Starting from #1, he knows he cannot pick anything bigger then 49 because if he did, then #2 only have to leave 3 beans for #3 #4 & #5 then he'll live. e.g. #1 picked 53 then #2 picks 100-53-3=44. then A,C,D,E all died. e.g. #1=53, #2=(100-53-3)=44, #3=1, #4=1, #5=1. The best chance for #1 is to pick anything less then or equal the median 20 (100 divided by 5). In fact anything between 3-20 won't change the result. Let's say #1 pick 20. . m3 P9 b$ a/ a: X% n: I+ T
tvb now,tvbnow,bttvb2 c$ ^- m9 X0 l8 P w& J
Now #2 knows whatever he picks, #3 will take the median between him & #1 e.g. now #1 picked 20, if he pick 6 then #3 will pick 13 putting him either being the lowest or highest. He cannot allow that so the best chance is to match #1, so he picked 20 as well.
9 g, C1 r9 p, w6 h" h8 @TVBNOW 含有熱門話題，最新最快電視，軟體，遊戲，電影，動漫及日常生活及興趣交流等資訊。
) S# _) b+ w/ n公仔箱論壇#3 did the obvious choice 40 divided by 2 =20, so he picked 20
+ _+ E6 J4 P, G, }* z& ~3 STVBNOW 含有熱門話題，最新最快電視，軟體，遊戲，電影，動漫及日常生活及興趣交流等資訊。
5 b( V% @3 T E. `tvb now,tvbnow,bttvb#4 base on knowing the median rule take 60 divided by 3 =20, so he picked 20 as well.TVBNOW 含有熱門話題，最新最快電視，軟體，遊戲，電影，動漫及日常生活及興趣交流等資訊。; s( L$ M. y' T
9 `$ Z( c7 [; F& ~$ j& G- M p#5 same as above, he takes 80 divided by 4 =20, picked 20 as well.公仔箱論壇2 V5 Q' s/ _5 S9 L4 Y& f
$ f2 L, Z" c7 Wtvb now,tvbnow,bttvbEnded all have the same number and all died. |
發表於 2006-12-9 12:41 AM
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