1. divide 6 and 6, both sides will not equal $ i; `4 C/ I! Ctvb now,tvbnow,bttvb2. take any side of the 6, divide then 3 and 3, again both sides will not equal - }! n8 C' o; I1 n5 Y; _3. take any 2 and weigh them 6 B+ z1 [: ^" X$ k6 R ctvb now,tvbnow,bttvbif they equal, the one left is the ball.
發表於 2007-6-16 08:33 PM
| 
