put six on each side first7 l/ R6 Z) c% y: {+ G0 z5 Q
6 ?; d& r; `, K) b Utvb now,tvbnow,bttvbfrom the heavier six, split it to three on each side
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then there is three left, put one on each side, if one is heavier then that is it, if they are balanced then last one is heavy one |