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答案!!!!!!!!!答案!!!!!!!!!!!答案!!!!!!!!!!!!!1
^:)^ >:D<
thx
let cc
not possible
不知道要怎麼做阿??
hao

the model answer is stupid

there got more simple way to do it, just read my way, the one i answered before
the
see 了
第一次,一边5个称,若质量没有异常就只称剩下的2个就知道异常的那个了;若有异常就把异常的那5个用一边2个称第二次,若没有异常就是剩下的那个异常了,若有异常就把异常的那2个再2一边1个称第三次就知道了
how?
先分3个一堆
  E! h6 q8 d1 c: f) |4 j1 j0 }: i公仔箱論壇共四堆
; L! @& x9 M) O4 R& ?3 d! jos.tvboxnow.com称两次得出异常的在那一堆,其轻重
. z1 S5 Z+ A& L! X8 Y. ]/ a* ytvb now,tvbnow,bttvb在异常的那一堆中在称一次
6 k) x) J% i1 [9 N, o- h/ c就可以找到了
divde the 12 balls into 3 sets of 4. ( Q; f4 K8 a6 k: x/ P0 K
weight any 2 sets.
  M+ {( U& Z3 O. f6 [" vos.tvboxnow.comif the 2 sets are equal, then you know the heavy one is in the third
  I5 Q. `4 G: J* ]. F5 T2 hif one of the 2 is heavier, then the heavy one is in that set+ t0 Z. `) f8 s
then divide the 4 balls into 2.  R( R. Z7 P0 q8 S8 U$ w
weigh themtvb now,tvbnow,bttvb* F1 E2 l2 e2 s
and divide the heavier into 1os.tvboxnow.com7 w8 x) a: ?/ `) h0 c& V
and weight them.- ?) {, c- n4 w7 ~5 d
3 x weighing and get the ans.  
, o+ [8 z, o; G/ D4 s0 ?0 a0 Jtvb now,tvbnow,bttvbin less than 15 secs.
1. 6 aside and weight.
3 l! N7 H# \" s  y* {& `5 atvb now,tvbnow,bttvb2. heavier side from (1), 3 aside weight again.
: s& S2 @8 G$ F7 {8 {; ltvb now,tvbnow,bttvb3. heavier side from (2), take 2 out of 3 to weight. If equal weight the one not on the scale is the heavier one. else the heavier one on the scale is the odd one.
2 J1 ~: S! Y$ Y: T( J$ j" t6 c9 {5 G. Y8 K3 J$ a1 y2 Y/ w
but i have a question. 重量異常 can be heavier or lighter.... so......
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