返回列表 回復 發帖
答案!!!!!!!!!答案!!!!!!!!!!!答案!!!!!!!!!!!!!1
^:)^ >:D<
thx
let cc
not possible
不知道要怎麼做阿??
hao

the model answer is stupid

there got more simple way to do it, just read my way, the one i answered before
the
see 了
第一次,一边5个称,若质量没有异常就只称剩下的2个就知道异常的那个了;若有异常就把异常的那5个用一边2个称第二次,若没有异常就是剩下的那个异常了,若有异常就把异常的那2个再2一边1个称第三次就知道了
how?
先分3个一堆
: D: D1 v: c" N" Ctvb now,tvbnow,bttvb共四堆
5 l6 ^% j& y- s! i' v5 m称两次得出异常的在那一堆,其轻重
1 r' e: i( R2 p) r. n" D# ?os.tvboxnow.com在异常的那一堆中在称一次; T7 e; U, \( r1 Z# }
就可以找到了
divde the 12 balls into 3 sets of 4. 2 ~6 ~# W  J+ n( a6 c" S" y
weight any 2 sets.
+ ?6 m: ^; {3 M+ d6 Eos.tvboxnow.comif the 2 sets are equal, then you know the heavy one is in the thirdtvb now,tvbnow,bttvb2 b# V( e3 n  I6 Y
if one of the 2 is heavier, then the heavy one is in that set  O" J" L8 _% r$ e' f9 A
then divide the 4 balls into 2.
: U4 e. z8 Q" y# k; f. |# e! Z9 y8 ^os.tvboxnow.comweigh them
4 ]# @$ K' Z" ?" ?tvb now,tvbnow,bttvband divide the heavier into 1
/ F5 q6 j8 D' d# ^9 u- L7 r公仔箱論壇and weight them.
# a- j$ D( m+ C' u- q! }9 _" q' X0 G3 x weighing and get the ans.  tvb now,tvbnow,bttvb" A' v5 T  M3 p  d# r, `7 z, e
in less than 15 secs.
1. 6 aside and weight.tvb now,tvbnow,bttvb5 W& \# j9 f$ i8 i9 k, X( F
2. heavier side from (1), 3 aside weight again.  y, w# N3 p: C4 A
3. heavier side from (2), take 2 out of 3 to weight. If equal weight the one not on the scale is the heavier one. else the heavier one on the scale is the odd one.
' j& A$ o# @" d& g9 Y5 o7 ?% ~
. r; X2 q3 i8 B" S( H8 h* yTVBNOW 含有熱門話題,最新最快電視,軟體,遊戲,電影,動漫及日常生活及興趣交流等資訊。but i have a question. 重量異常 can be heavier or lighter.... so......
返回列表