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答案!!!!!!!!!答案!!!!!!!!!!!答案!!!!!!!!!!!!!1
^:)^ >:D<
thx
let cc
not possible
不知道要怎麼做阿??
hao

the model answer is stupid

there got more simple way to do it, just read my way, the one i answered before
the
see 了
第一次,一边5个称,若质量没有异常就只称剩下的2个就知道异常的那个了;若有异常就把异常的那5个用一边2个称第二次,若没有异常就是剩下的那个异常了,若有异常就把异常的那2个再2一边1个称第三次就知道了
how?
先分3个一堆
' P( ?  U; C% |& ]共四堆, D$ k% Z9 k0 V6 k
称两次得出异常的在那一堆,其轻重tvb now,tvbnow,bttvb7 i  q0 V0 |% r& ^' B+ U
在异常的那一堆中在称一次tvb now,tvbnow,bttvb. {: {# ?, E( c7 o( |; R0 t
就可以找到了
divde the 12 balls into 3 sets of 4. 7 P& N2 h. N1 O& _
weight any 2 sets.% _- W9 S- c0 p
if the 2 sets are equal, then you know the heavy one is in the third
* \. u8 d" M% y1 V1 {TVBNOW 含有熱門話題,最新最快電視,軟體,遊戲,電影,動漫及日常生活及興趣交流等資訊。if one of the 2 is heavier, then the heavy one is in that set+ ^$ ^- G; m3 X, _4 a
then divide the 4 balls into 2.
: X& I2 Q8 V- oTVBNOW 含有熱門話題,最新最快電視,軟體,遊戲,電影,動漫及日常生活及興趣交流等資訊。weigh them( m% l' \& t% ~6 [# V2 V
and divide the heavier into 1TVBNOW 含有熱門話題,最新最快電視,軟體,遊戲,電影,動漫及日常生活及興趣交流等資訊。" {! |# b1 M3 ~3 m
and weight them.
3 H& ~6 A& j% p. E  P; n公仔箱論壇3 x weighing and get the ans.  
; h& O4 x8 m; W% m3 Din less than 15 secs.
1. 6 aside and weight.8 R4 G, Y. R& }6 e0 L
2. heavier side from (1), 3 aside weight again.
$ j! W: `0 b; _tvb now,tvbnow,bttvb3. heavier side from (2), take 2 out of 3 to weight. If equal weight the one not on the scale is the heavier one. else the heavier one on the scale is the odd one.
8 X( ^: ]5 [& Q, P1 H7 bTVBNOW 含有熱門話題,最新最快電視,軟體,遊戲,電影,動漫及日常生活及興趣交流等資訊。
. R! I0 C6 \4 f# i; E$ Pos.tvboxnow.combut i have a question. 重量異常 can be heavier or lighter.... so......
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