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答案!!!!!!!!!答案!!!!!!!!!!!答案!!!!!!!!!!!!!1
^:)^ >:D<
thx
let cc
not possible
不知道要怎麼做阿??
hao

the model answer is stupid

there got more simple way to do it, just read my way, the one i answered before
the
see 了
第一次,一边5个称,若质量没有异常就只称剩下的2个就知道异常的那个了;若有异常就把异常的那5个用一边2个称第二次,若没有异常就是剩下的那个异常了,若有异常就把异常的那2个再2一边1个称第三次就知道了
how?
先分3个一堆4 }' q3 n+ \: _/ \6 v5 o0 j
共四堆+ W4 z6 m# m, u( y2 \
称两次得出异常的在那一堆,其轻重
' O: _) X( a2 i9 ^  Qtvb now,tvbnow,bttvb在异常的那一堆中在称一次  A1 B& b6 @  S3 z
就可以找到了
divde the 12 balls into 3 sets of 4.
4 v' S+ n3 b" R. w% `6 x" cweight any 2 sets.( O) ]& E! c% `0 M3 }4 K: n
if the 2 sets are equal, then you know the heavy one is in the thirdos.tvboxnow.com, m, l- n# G' [  S; \4 ?
if one of the 2 is heavier, then the heavy one is in that settvb now,tvbnow,bttvb6 r9 R7 V! [- P8 ~& x! Y: ^
then divide the 4 balls into 2.# Z4 e- @: t) _7 W
weigh them
+ ?  N! |- {* }2 I0 K1 |, ?5 Hand divide the heavier into 1  m" c9 i- I1 h. e
and weight them.
  y. h: J* |0 k8 A) Aos.tvboxnow.com3 x weighing and get the ans.  
/ K+ {. a  u$ G) uos.tvboxnow.comin less than 15 secs.
1. 6 aside and weight.
$ Y/ c" R4 j% j; a+ L2. heavier side from (1), 3 aside weight again.
. V" ]; h7 G. a8 R7 B8 b4 ^3. heavier side from (2), take 2 out of 3 to weight. If equal weight the one not on the scale is the heavier one. else the heavier one on the scale is the odd one.
4 S$ Z5 F9 ~* W" A( L9 }9 v4 Wtvb now,tvbnow,bttvb
8 h( I1 U  {9 v; V6 `tvb now,tvbnow,bttvbbut i have a question. 重量異常 can be heavier or lighter.... so......
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