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答案!!!!!!!!!答案!!!!!!!!!!!答案!!!!!!!!!!!!!1
^:)^ >:D<
thx
let cc
not possible
不知道要怎麼做阿??
hao

the model answer is stupid

there got more simple way to do it, just read my way, the one i answered before
the
see 了
第一次,一边5个称,若质量没有异常就只称剩下的2个就知道异常的那个了;若有异常就把异常的那5个用一边2个称第二次,若没有异常就是剩下的那个异常了,若有异常就把异常的那2个再2一边1个称第三次就知道了
how?
先分3个一堆os.tvboxnow.com( x+ v# N' @; i+ m: Y, P& I
共四堆
, y& H- x2 B9 [2 Z) Y称两次得出异常的在那一堆,其轻重+ d. x& J, D. k9 c8 ]
在异常的那一堆中在称一次, D, J/ b5 ?" R7 }8 Y8 z+ V
就可以找到了
divde the 12 balls into 3 sets of 4.
, l* ]5 l9 E7 zTVBNOW 含有熱門話題,最新最快電視,軟體,遊戲,電影,動漫及日常生活及興趣交流等資訊。weight any 2 sets.
* C. y# z! J/ I' y; y: _5 ~os.tvboxnow.comif the 2 sets are equal, then you know the heavy one is in the third6 [% l, f1 D, V! K; o7 y
if one of the 2 is heavier, then the heavy one is in that set公仔箱論壇9 h) i' p% W" ], D$ G  S, a
then divide the 4 balls into 2.
+ J% w) f4 C, V$ i+ p& Dweigh them: d# r* |" W7 o* a
and divide the heavier into 1
3 H- P+ S" q/ ]1 x+ ?; n0 ]os.tvboxnow.comand weight them.* I! ?5 y6 \2 `$ H$ O' `
3 x weighing and get the ans.  , K$ e9 ?/ T* g0 l0 A- i
in less than 15 secs.
1. 6 aside and weight.TVBNOW 含有熱門話題,最新最快電視,軟體,遊戲,電影,動漫及日常生活及興趣交流等資訊。; z4 m- j5 U! h' T- [
2. heavier side from (1), 3 aside weight again.os.tvboxnow.com/ ]$ A$ H  d9 q$ ]
3. heavier side from (2), take 2 out of 3 to weight. If equal weight the one not on the scale is the heavier one. else the heavier one on the scale is the odd one.
3 O3 k& e$ D+ x9 p* wos.tvboxnow.com& b& U4 A1 ~1 W
but i have a question. 重量異常 can be heavier or lighter.... so......
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