zzzhao

see xia da an

yaukinman

want to know

zb7803

我来看看

lkhlewis

青蓮居士

check ans..

mkl2345

6 and 6 then 3 and 3 then 1 and 1

gg2968

5識答？

pyhzf

thank you

XYZCrux

将12个乒乓球分成平均两份，称一次
. a4 a6 a" |3 D$ |& c1 }os.tvboxnow.com将比较重的那份再平均分成两份成一次- A& C. v9 ~, X, i
剩下3个随意拿两个来称，如果天平平衡就是第三个，如果不平衡就是重的那个

wtfka

thank

agnesium

Thanks!

ban0212

第一次系一边四个，一边四个秤既

westgun

1 - compare 4 with 4
3 k6 p' m- G7 n( t2 M5 C2 h3 Gif  (4v4)= same that means the rest of 4 is got more weight公仔箱論壇" y8 K1 i4 |! X* n6 J
    then goto 2 - compare rest of(4)  - 2 with 2 tvb now,tvbnow,bttvb- |) W& Y! a- Q: t
           if (left side is more weight)! ~( K* n+ @! ?7 F
              then goto 3 - compare last (left side of ( 2) - 1 with 1 => get answer
! v: {  v! M8 Ktvb now,tvbnow,bttvb          else ( right side is more weight)os.tvboxnow.com9 y) F9 m$ H& X3 J
              then goto 3 - compare last (right side of (2) - 1 with 1 => get answer) k- ~% K$ }0 t' K6 A. E  ~
else ( the left 4) then compare with above  , or right 4 also can compare above method...

ywl01

想了好久都不行

zhengfaxuezi

我的做法与4楼的做法一致，这样应该可以排除出来。但这个题目有个漏洞，只说重量异常，没说是重了，还是轻了。