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see xia da an
want to know
我来看看
check ans..
6 and 6 then 3 and 3 then 1 and 1
5識答?
thank you
将12个乒乓球分成平均两份,称一次9 M5 p7 N0 k4 d+ `/ A9 _4 @
将比较重的那份再平均分成两份成一次
; @) ~* h7 \7 ~; {- J剩下3个随意拿两个来称,如果天平平衡就是第三个,如果不平衡就是重的那个
thank
Thanks!
第一次系一边四个,一边四个秤既
1 - compare 4 with 4
& d$ k0 F# H4 F6 u% m4 t8 N+ u# dtvb now,tvbnow,bttvbif  (4v4)= same that means the rest of 4 is got more weight
9 c5 A! i( ^% z; }/ i! pos.tvboxnow.com    then goto 2 - compare rest of(4)  - 2 with 2 TVBNOW 含有熱門話題,最新最快電視,軟體,遊戲,電影,動漫及日常生活及興趣交流等資訊。9 Z" E3 J" {* R* X: q: R# Z9 l
           if (left side is more weight)os.tvboxnow.com  @/ n% y) ]* V6 V2 J+ U7 m
              then goto 3 - compare last (left side of ( 2) - 1 with 1 => get answer
  g/ V8 r3 K' L9 y. m& q; D4 x          else ( right side is more weight)
- a; w: [' c4 @/ Dos.tvboxnow.com              then goto 3 - compare last (right side of (2) - 1 with 1 => get answer: v9 g! [4 t5 l+ e8 K% ~
else ( the left 4) then compare with above  , or right 4 also can compare above method...
想了好久都不行
我的做法与4楼的做法一致,这样应该可以排除出来。但这个题目有个漏洞,只说重量异常,没说是重了,还是轻了。
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