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see xia da an
want to know
我来看看
check ans..
6 and 6 then 3 and 3 then 1 and 1
5識答?
thank you
将12个乒乓球分成平均两份,称一次os.tvboxnow.com- ?6 G" [# z: O. A% J
将比较重的那份再平均分成两份成一次
# a  O- i8 Y6 q; x剩下3个随意拿两个来称,如果天平平衡就是第三个,如果不平衡就是重的那个
thank
Thanks!
第一次系一边四个,一边四个秤既
1 - compare 4 with 4. [* v) m- q% v# i9 P9 L* G
if  (4v4)= same that means the rest of 4 is got more weighttvb now,tvbnow,bttvb& D) n* v; l! z1 m  e
    then goto 2 - compare rest of(4)  - 2 with 2 tvb now,tvbnow,bttvb* C7 f+ w& m) W- T1 D4 k7 g
           if (left side is more weight)tvb now,tvbnow,bttvb1 k3 ~& E/ z, y* @5 e+ x  m) V2 C% a
              then goto 3 - compare last (left side of ( 2) - 1 with 1 => get answer
9 [0 q. `2 B3 U, z3 W, d" t          else ( right side is more weight)
# E& D  W) i* G( G' V: q              then goto 3 - compare last (right side of (2) - 1 with 1 => get answer
8 Q2 I, b# h) s" N2 S9 Q2 |# ntvb now,tvbnow,bttvbelse ( the left 4) then compare with above  , or right 4 also can compare above method...
想了好久都不行
我的做法与4楼的做法一致,这样应该可以排除出来。但这个题目有个漏洞,只说重量异常,没说是重了,还是轻了。
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