Exactly, done in less than 10 seconds, not sure why the host make it so complicated, he/she must have misunderstood the original question before posting.
( T; X: {% t' v4 S" r# q$ ~tvb now,tvbnow,bttvb+ n# Z8 g. V# n2 @6 h7 v$ t5 g+ G9 P
Start with 12 balls, weight 6 - 6 on scale, the take the 6 from the heavier side and weight 3 - 3, then take the 2 out of 3 from the heavier side weight again, if these 2 balances then the heaviest ball is the remaining 1. (please oh please don't ask what happens if these 2 our of 3 does not balance). |
發表於 2009-4-19 08:53 PM
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