Well..divided into 6/6 first to define a heavier group is certainly right. Randomly select 3/3 will result another heavier group.
* z) M$ ?/ @/ U: d. Kos.tvboxnow.comThe problem is we don't know the weight of each individual ball, so it will not be accurate to figure out which ball is irregular by only weight them once.
. n, _7 @9 O7 E/ R6 E, \6 M, etvb now,tvbnow,bttvb |