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直接看答案!
i find one solution that is similar
3 {# X3 r& z$ R# Q1 ^but i can't specify the heavier one is abnormal or the lighter one is abnormal when the case that has only two balls left....
5 @( i4 P" j9 [: h; e% dtvb now,tvbnow,bttvbmaybe there is a better one, let me see sin
it is already good IQ if you can understand the answer......
pretty difficult... needa see answer
!!!!!!!!!!!!!!!!!!!!!!!!!

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thanks for share:onion14:

wow

is that really possible, i want to know
interesting ...
.... thx for sharing !
ddddd
actually this question always have someone asked, the calculation is very complicated, should give a no. of each ball, and first weight it in 6-6, and .... forgot...
how oh???
Let me see the answer
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