divide 12 into 6 one side n balance it..
- J/ S8 k8 _* @+ Etvb now,tvbnow,bttvbden take da heavier side which is 6 n divide into 2 parts again..
& f2 _+ d$ `$ s, O6 _9 y( V B3 one side n another 3 another side..5 D; ]6 @* b6 M$ h0 [$ l- f+ S9 d( `
den u take da heavier part again... w$ i( T8 j% B
now u left 3 pingpong.. u can simply choose 2 of it n balance again..+ J6 t6 u3 r$ B3 |) z4 p
if one of it is da heavy wan.. da balance will drop one side.. if both are da same.. den da balance hav no changes n da leftover one is da heavy wan |