hoeteck

i wan to know

wenlove08

thx.~

caseylee0427

thank you for sharing

rock5356466

look at it

leo_04236

i noe de ans cauz 1 do b4 already ^^tvb now,tvbnow,bttvb( s( ^' c1 Z5 \" c# x# G
1st u divide the ball into two group (i group 6 ball)os.tvboxnow.com, n% z* Z) |! Q
then 称 them c which side is the heavy
* P' @3 w3 `3 o# S# N3 kthen use the heavy side divide into 3 group 1group contain 2 ball 称 the 1st n 2nd group if its balance use the 3th group TVBNOW 含有熱門話題，最新最快電視，軟體，遊戲，電影，動漫及日常生活及興趣交流等資訊。2 Q( f! t+ I; O5 D
if not balance take the heavy and then
  a9 V- ^4 U9 wtake the heavy group divided into 2 group i group contain 1 ball than 称 it os.tvboxnow.com8 l; C. K* Y, M: f' N6 b( m% |
than the heavy ball is the ball u wan

sam5881

how??????????

ar_yuo

Oh..i did the same way as the first answer~am i wrong??Let me check~:onion18:

单身汉

分三次算的话，每次分四粒来算，意思说当有一边较重时，只需要随意将其中六粒拿出来就知道那一粒是异常的了:onion14:
$ v+ m: n- l  c: ^" t7 z公仔箱論壇（不知各位知不知道小弟说的解答，因为小弟不擅长解说）

ldcloud

thx 4 sharing

烟灰缸

顶．．．．．．

烟灰缸

顶．．．．．．．

haharinny

简单到。。分3份。。每份4个。。第一次称。。必然知道3份中哪份包括异常的。。第二次..把包括的那份2：2的称。。又知道异常的一边" R0 B4 M1 D- m! X4 n( Y/ {# \1 r
然后。。1：1。。就知道了··

htq771112

看解答!!!!!!!!!!!!!!

puki

cccccc

Hikouseki

idk..show me