hoeteck

i wan to know

wenlove08

thx.~

caseylee0427

thank you for sharing

rock5356466

look at it

leo_04236

i noe de ans cauz 1 do b4 already ^^
2 {' ^! o4 c- Y9 W: v1st u divide the ball into two group (i group 6 ball)% w( F, I) Q& @8 X) d% Q
then 称 them c which side is the heavy os.tvboxnow.com. i3 y5 A0 ]4 O# l( F$ u
then use the heavy side divide into 3 group 1group contain 2 ball 称 the 1st n 2nd group if its balance use the 3th group
, p& D- C$ l& Q  L8 Iif not balance take the heavy and then tvb now,tvbnow,bttvb5 R& Q# c1 B/ C- n) i
take the heavy group divided into 2 group i group contain 1 ball than 称 it % N4 d$ v$ l% J6 f5 M. K/ z' b* w
than the heavy ball is the ball u wan

sam5881

how??????????

ar_yuo

Oh..i did the same way as the first answer~am i wrong??Let me check~:onion18:

单身汉

分三次算的话，每次分四粒来算，意思说当有一边较重时，只需要随意将其中六粒拿出来就知道那一粒是异常的了:onion14:
. J1 `0 n! C/ @tvb now,tvbnow,bttvb（不知各位知不知道小弟说的解答，因为小弟不擅长解说）

ldcloud

thx 4 sharing

烟灰缸

顶．．．．．．

烟灰缸

顶．．．．．．．

haharinny

简单到。。分3份。。每份4个。。第一次称。。必然知道3份中哪份包括异常的。。第二次..把包括的那份2：2的称。。又知道异常的一边
) g3 t. ^; S1 k# G然后。。1：1。。就知道了··

htq771112

看解答!!!!!!!!!!!!!!

puki

cccccc

Hikouseki

idk..show me