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回復 #1 MagicAndy 的帖子

i wan to know
thx.~
thank you for sharing
look at it
i noe de ans cauz 1 do b4 already ^^
. C+ a5 A8 S, {- l5 qtvb now,tvbnow,bttvb1st u divide the ball into two group (i group 6 ball)公仔箱論壇" P& x) g5 [; |" l* z# t
then 称 them c which side is the heavy 公仔箱論壇3 O0 m5 g% c5 ?% U& i
then use the heavy side divide into 3 group 1group contain 2 ball 称 the 1st n 2nd group if its balance use the 3th group
' ~2 V% v8 ^3 aif not balance take the heavy and then
2 R* R( N; M- ]8 E. O# Ktvb now,tvbnow,bttvbtake the heavy group divided into 2 group i group contain 1 ball than 称 it os.tvboxnow.com* g3 M: `# ], P  b0 {& l. T& |
than the heavy ball is the ball u wan

回復 #1 MagicAndy 的帖子

how??????????
Oh..i did the same way as the first answer~am i wrong??Let me check~:onion18:
分三次算的话,每次分四粒来算,意思说当有一边较重时,只需要随意将其中六粒拿出来就知道那一粒是异常的了:onion14: 3 g6 d! A) g7 X5 h$ e  Z% {
(不知各位知不知道小弟说的解答,因为小弟不擅长解说)
thx 4 sharing
顶......

回復 #1 MagicAndy 的帖子

顶.......
简单到。。分3份。。每份4个。。第一次称。。必然知道3份中哪份包括异常的。。第二次..把包括的那份2:2的称。。又知道异常的一边
. D* l/ ~. I" T8 h) Y, E然后。。1:1。。就知道了··
看解答!!!!!!!!!!!!!!
cccccc
idk..show me
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