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回復 #1 MagicAndy 的帖子

i wan to know
thx.~
thank you for sharing
look at it
i noe de ans cauz 1 do b4 already ^^公仔箱論壇* q* Q1 _' B; Q7 D) M
1st u divide the ball into two group (i group 6 ball)os.tvboxnow.com5 s) c' d  E# I" N4 l
then 称 them c which side is the heavy 1 z& G1 K6 A0 ^6 a. i7 O  b
then use the heavy side divide into 3 group 1group contain 2 ball 称 the 1st n 2nd group if its balance use the 3th group tvb now,tvbnow,bttvb. c4 h+ F4 E! H. r- y  c0 @5 o
if not balance take the heavy and then
8 W2 k& H  t/ V" j2 Xos.tvboxnow.comtake the heavy group divided into 2 group i group contain 1 ball than 称 it
0 }/ G8 @' w0 J9 @5 z; Xthan the heavy ball is the ball u wan

回復 #1 MagicAndy 的帖子

how??????????
Oh..i did the same way as the first answer~am i wrong??Let me check~:onion18:
分三次算的话,每次分四粒来算,意思说当有一边较重时,只需要随意将其中六粒拿出来就知道那一粒是异常的了:onion14:
* {" j7 P  G# n, y, Q  S(不知各位知不知道小弟说的解答,因为小弟不擅长解说)
thx 4 sharing
顶......

回復 #1 MagicAndy 的帖子

顶.......
简单到。。分3份。。每份4个。。第一次称。。必然知道3份中哪份包括异常的。。第二次..把包括的那份2:2的称。。又知道异常的一边公仔箱論壇" `' M3 \, Y# y$ S  t' h
然后。。1:1。。就知道了··
看解答!!!!!!!!!!!!!!
cccccc
idk..show me
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