hoeteck

i wan to know

wenlove08

thx.~

caseylee0427

thank you for sharing

rock5356466

look at it

leo_04236

i noe de ans cauz 1 do b4 already ^^
) G# J" A2 P2 ~. Q) ?& dos.tvboxnow.com1st u divide the ball into two group (i group 6 ball)! [& Z( ^$ C+ }, v' @
then 称 them c which side is the heavy # {8 r1 n2 I% f" f% v6 F
then use the heavy side divide into 3 group 1group contain 2 ball 称 the 1st n 2nd group if its balance use the 3th group
( Z& d7 X( p: b' n& M: Y+ jos.tvboxnow.comif not balance take the heavy and then
7 K( V/ W  z, M% ]& E' ^take the heavy group divided into 2 group i group contain 1 ball than 称 it & S3 E% ~7 C# ~- ^  m7 ^
than the heavy ball is the ball u wan

sam5881

how??????????

ar_yuo

Oh..i did the same way as the first answer~am i wrong??Let me check~:onion18:

单身汉

分三次算的话，每次分四粒来算，意思说当有一边较重时，只需要随意将其中六粒拿出来就知道那一粒是异常的了:onion14:
' ?- F- D- Y" J( |! h, ^公仔箱論壇（不知各位知不知道小弟说的解答，因为小弟不擅长解说）

ldcloud

thx 4 sharing

烟灰缸

顶．．．．．．

烟灰缸

顶．．．．．．．

haharinny

简单到。。分3份。。每份4个。。第一次称。。必然知道3份中哪份包括异常的。。第二次..把包括的那份2：2的称。。又知道异常的一边
9 V0 `+ D- L4 i公仔箱論壇然后。。1：1。。就知道了··

htq771112

看解答!!!!!!!!!!!!!!

puki

cccccc

Hikouseki

idk..show me