That is a very simple mathematics question.
- y3 U) Z4 W0 p* G+ w7 o, ?; Ltvb now,tvbnow,bttvbLet x = Male, y = Female, z = Child4 f( s7 \" }2 M2 D2 a
6x + 3y + z/2 = 100 Formula 1tvb now,tvbnow,bttvb( [- g# t2 q0 P9 ~- O# Q: \" {
x + y + z = 100 Formula 2
6 g$ J0 i1 p) los.tvboxnow.comSimplify Formula 2 into z, we get z = 100 - x - y Formula 3os.tvboxnow.com) E R/ M9 z" E
Sub Formula 3 into Formula 1, we get 6x + 3y + ( 100 - x - y )/2 = 100 Formula 4: P) n9 Z3 j, D& s7 {) E- k0 b# D5 d
Formula 4 can change into 11x + 5y = 100 Formula 5/ N6 A/ O8 i2 Q/ G* a1 m
In Formula 5, x can only be 0 - 9, otherwise y will be negative number which we dont want.TVBNOW 含有熱門話題,最新最快電視,軟體,遊戲,電影,動漫及日常生活及興趣交流等資訊。" L P& S" B0 t* E/ ?1 P* x
And between 0 and 9, only 0 can give me a single number of y. So, x has to be 0 and y have to be 20. Then put x and y back to formula 1, we get z = 80.
3 Z( ~3 v' L, Z$ d3 N S1 g7 l公仔箱論壇Eventually, the answer is 20 female and 80 children and no male. |