That is a very simple mathematics question.
+ _* H: w" y) y; ]tvb now,tvbnow,bttvbLet x = Male, y = Female, z = Child0 v1 y* i! j3 X: \( c
6x + 3y + z/2 = 100 Formula 1
/ Q% |/ {% F5 E5 f$ qx + y + z = 100 Formula 2
8 N" j7 I) r6 _+ [8 J- }公仔箱論壇Simplify Formula 2 into z, we get z = 100 - x - y Formula 3
- e w* B. m$ bos.tvboxnow.comSub Formula 3 into Formula 1, we get 6x + 3y + ( 100 - x - y )/2 = 100 Formula 4os.tvboxnow.com- s: l( S( q: L! F9 w% f+ U$ ?
Formula 4 can change into 11x + 5y = 100 Formula 5公仔箱論壇% l. [$ g0 W. F5 Y
In Formula 5, x can only be 0 - 9, otherwise y will be negative number which we dont want.
7 T& Z8 L" ^0 H& `" O7 ~8 Y2 mos.tvboxnow.comAnd between 0 and 9, only 0 can give me a single number of y. So, x has to be 0 and y have to be 20. Then put x and y back to formula 1, we get z = 80.
( a5 Z8 D9 S( ]& C/ CTVBNOW 含有熱門話題,最新最快電視,軟體,遊戲,電影,動漫及日常生活及興趣交流等資訊。Eventually, the answer is 20 female and 80 children and no male. |