That is a very simple mathematics question. + X7 c/ M4 E1 M1 I; z+ h5 q+ X D3 lLet x = Male, y = Female, z = Child . s/ V4 I2 P( Y# A; H3 J% \, jtvb now,tvbnow,bttvb6x + 3y + z/2 = 100 Formula 1 ' n2 l; r; n$ i- c7 jtvb now,tvbnow,bttvbx + y + z = 100 Formula 2 % i5 r" N9 G/ rtvb now,tvbnow,bttvbSimplify Formula 2 into z, we get z = 100 - x - y Formula 3tvb now,tvbnow,bttvb$ b6 q# A) ]+ G# ~
Sub Formula 3 into Formula 1, we get 6x + 3y + ( 100 - x - y )/2 = 100 Formula 4 % l5 A9 ?3 z$ @* U* eTVBNOW 含有熱門話題，最新最快電視，軟體，遊戲，電影，動漫及日常生活及興趣交流等資訊。Formula 4 can change into 11x + 5y = 100 Formula 5 2 X8 y. V( p! o1 k$ e5 o8 RIn Formula 5, x can only be 0 - 9, otherwise y will be negative number which we dont want. / |7 Z# H. y! G( S7 O6 zAnd between 0 and 9, only 0 can give me a single number of y. So, x has to be 0 and y have to be 20. Then put x and y back to formula 1, we get z = 80.) D! [1 S8 M& M# o p! Z
Eventually, the answer is 20 female and 80 children and no male.作者: alan1234 時間: 2007-10-14 12:19 AM 標題: two answers
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11X must be 0 or multiple of 5tvb now,tvbnow,bttvb; J$ f! o" r. H2 E' U
that meanz x must be 0 or 5作者: manstein 時間: 2007-10-15 08:28 PM
